Answer:
The image coordinates are:
A'(0, 0)
B'(-8, -8)
C'(4, -8)
The graph of the image coordinates attached below.
The image triangle A'B'C' is illustrated in green color.
Step-by-step explanation:
Let the points of a triangle be
We need to determine the graph of the image of this triangle after a dilation with a scale factor of 2 centered at the origin.
- As scale factor > 0, thus the image will be enlarged.
A dilation by a scale factor of 2 centered at the origin means the coordinates of the image can be obtained by multiplying the original coordinates with 2.
Next, the rule of dilation by a scale factor of 2 is given by
Dilation: (x, y) → (2x, 2y), centered at (0, 0)
P(x, y) → P' (2x, 2y)
A(0, 0) → A' (2(0), 2(0)) → A'(0, 0)
B(-4, -4) → B' (2(-4), 2(-4)) → B'(-8, -8)
C(2,-4) → C' (2(2), 2(-4)) → C'(4, -8)
Therefore, the image coordinates are:
The graph of the image coordinates attached below.
The image triangle A'B'C' is illustrated in green color.
