Respuesta :

Answer:

y = - [tex]\frac{1}{12}[/tex] x + [tex]\frac{127}{12}[/tex]

Step-by-step explanation:

y = 12x - 9

Slope of line perpendicular to given is m = - [tex]\frac{1}{12}[/tex]

P(7, 10)

y - 10 = - [tex]\frac{1}{12}[/tex] (x - 7)

y = - [tex]\frac{1}{12}[/tex] x + [tex]\frac{127}{12}[/tex]

An equation of the line that passes through (7,10) and is perpendicular to the line y=12x−9 is y - 10 = -1/12(x-7)

The equation of a line in point-slope form is expressed as;

y - y0 = m(x-x0)

  • m is the slope of the line
  • (x0, y0) is any point on the line

Given the equation of a line y = 12x - 9

  • Slope = 12
  • Slope of the line perpendicular is -1/12

Substitute m = -1/12 and ()7, 10) into the equation above to have;

y - 10 = -1/12(x-7)

Hence an equation of the line that passes through (7,10) and is perpendicular to the line y=12x−9 is y - 10 = -1/12(x-7)

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