Respuesta :
Answer:
y = - [tex]\frac{1}{12}[/tex] x + [tex]\frac{127}{12}[/tex]
Step-by-step explanation:
y = 12x - 9
Slope of line perpendicular to given is m = - [tex]\frac{1}{12}[/tex]
P(7, 10)
y - 10 = - [tex]\frac{1}{12}[/tex] (x - 7)
y = - [tex]\frac{1}{12}[/tex] x + [tex]\frac{127}{12}[/tex]
An equation of the line that passes through (7,10) and is perpendicular to the line y=12x−9 is y - 10 = -1/12(x-7)
The equation of a line in point-slope form is expressed as;
y - y0 = m(x-x0)
- m is the slope of the line
- (x0, y0) is any point on the line
Given the equation of a line y = 12x - 9
- Slope = 12
- Slope of the line perpendicular is -1/12
Substitute m = -1/12 and ()7, 10) into the equation above to have;
y - 10 = -1/12(x-7)
Hence an equation of the line that passes through (7,10) and is perpendicular to the line y=12x−9 is y - 10 = -1/12(x-7)
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