Answer: B. 12.55
Step-by-step explanation:
Given: In a binomial event , the probability of success = 0.3
i.e. p =0.3
Then, q=1-P=1-03=0.7
The total number of trial performed n= 750
Now, the standard deviation of the proportion is given by :-
[tex]\sigma=\sqrt{npq}\\\\\Rightarrow\sigma=\sqrt{750\times0.3\times0.7}\\\\\Rightarrow\sigma=\sqrt{157.5}\\\\\Rightarrow\sigma=12.5499003\approx12.55[/tex]
Hence, the standard deviation of the possible outcomes = 12.55
