contestada

At 2:00 PM a car's speedometer reads 30 mi/h. At 2:20 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:20 the acceleration is exactly 60 mi/h2.

Respuesta :

Answer:

The correct answer will be "60 min/hour".

Step-by-step explanation:

At time 2:00 PM

A car reads = 30 mi/h

At time 2:20 PM

A car reads = 50 mi/h

Now,

At time 2:00 PM

t = 0

At time 2:20 PM

t = [tex]\frac{1}{3}[/tex]

[tex]v(0)=30[/tex]

[tex]v(\frac{1}{3})=50[/tex]

For MVT,

[tex]v'(c)=\frac{v(\frac{1}{3} -v(0))}{(\frac{1}{3} )}[/tex]

       [tex]=\frac{20}{\frac{1}{3} }[/tex]

       [tex]=60 \ min/hour[/tex]

Otras preguntas