Answer:
11.24m
Explanation:
What is the range of a projectile?
the range can be defined as the distance from the point of projection, where the projectile touches the ground again.
given data
∅=25°
initial speed= 12m/s
assuming g= 9.81m/s^2
The expression for the range is given as
R=(u^2sin2∅)/g
substituting we have
R=12^2sin(2*25)/9.81
R=144sin50/9.81
R=144*0.76/9.81
R=110.3/9.81
R=11.24m
the rock will land at 11.24m away from the buiding
