Complete Question
A certain university estimated that the proportion of students who prefer 2 day a week classes to 1 day a week classes was somewhere in the interval (0.451, 0.872) . If a 95% confidence interval was used, find the point estimate of the proportion and the margin of error
Answer:
The point estimate is [tex]\^ p =0.6615[/tex]
The margin of error is [tex]E = 0.2105[/tex]
Step-by-step explanation:
From the question we are that
The estimate of the proportion of students who prefer 2 day a week classes to 1 day a week classes is (0.451, 0.872)
Generally the point estimate is mathematically represented as
[tex]\^ p = \frac{ 0.872 + 0.451 }{2}[/tex]
=> [tex]\^ p =0.6615[/tex]
Generally the margin of error is mathematically represented as
[tex]E = \frac{0.872 - 0.451}{2}[/tex]
=> [tex]E = 0.2105[/tex]
