Respuesta :
Answer:
The correct answer is "4.8137 m³". The further explanation is given below.
Explanation:
Firstly we have to calculate the concentration of Se:
[tex]C = 0.0015 \ mg/L\times \frac{1g}{1000 mg}\times \frac{1 \ mol}{79 \ g}[/tex]
[tex]=1.9\times 10^{-8} \ mol/L[/tex]
Concentration the fish can take:
[tex]=0.04 \ mg/L\times \frac{1 \ g}{1000mg}\times \frac{1 \ mol}{79 \ g}[/tex]
According to the general dilution principle will be:
⇒ [tex]M_1V_1 = M_2V_2[/tex]
The volume that can take the farmer will be:
[tex]V_2 = 1.9\times 10^{-8} M\times \frac{5\times 10^3 \ L}{5.1\times 10-7 M}[/tex]
[tex]=186.27 \ L[/tex]
On converting this into m³, we get
= [tex]0.18627 \ m^3[/tex]
Finally the volume the farmer can remove would be:
[tex]V = 5-0.18627[/tex]
[tex]= 4.8137 \ m^3[/tex]
