Answer:
ρ = 4407.03 kg/m³
Explanation:
The Density of a metal alloy is given by the following equation:
1/ρ = m₁/ρ₁ + m₂/ρ₂ + m₃/ρ₃
where,
ρ = density of allow = ?
ρ₁ = density of Titanium (Ti) = 4540 kg/m³
ρ₂ = density of Aluminum (Al) = 2710 kg/m³
ρ₃ = density of Vanadium (V) = 6110 kg/m³
m₁ = mass fraction of Titanium (Ti) = 90% = 0.9
m₂ = mass fraction of Aluminum (Ti) = 6% = 0.06
m₁ = mass fraction of Vanadium (V) = 4% = 0.04
Therefore,
1/ρ = 0.9/(4540 kg/m³) + (0.06)/(2710 kg/m³) + (0.04)/(6110 kg/m³)
1/ρ = 1.9823 x 10⁺⁴ m³/kg + 0.2214 x 10⁻⁴ m³/kg + 0.0654 x 10⁻⁴ m³/kg
1/ρ = 2.2691 x 10⁻⁴ m³/kg
ρ = 1/(2.2691 x 10⁻⁴ m³/kg)
ρ = 4407.03 kg/m³
