Answer:
put 6 over 1 then look for the LCM of 7 and 1 the LCM is 7 then ask yourself how times does seven go into 7 one time right so multiply 1 by 3(2a - 1) then ask yourself how many times does 1 go into 7 it goes 7 times right multiply 7 by 6 so your equation is like this 3(2a - 1) = 42 open the bracket so it will be 6a - 3 = 42 collect the like terms so 3a = 42+3, 3a =45 , divide both sides by 3 so x =15
