1 Javier has at most $15.00 to spend today. He buys a bag of pretzels and a bottle of juice for $2.59. If gasoline at this store costs $3.39 per gallon, how many gallons of gasoline, to the nearest tenth of gallon, can Javier buy for his car?

We know that Javier has at most $15.00 to spend. In other words, the total cost after buying the snacks and gasoline must be less than or equal to 15.

He already bought a snack and a drink for a total of $2.59.

And each gallon of gasoline costs $3.39.

So, we can write the following inequality:

[tex]2.59+3.39g\leq 15.00[/tex]

To find how many galloons of gasoline Javier can buy, we will need to solve for g.

So, subtract 2.59 from both sides. This yields:

[tex]3.39g\leq12.41[/tex]

Divide both sides by 3.39:

[tex]g\leq3.66[/tex]

So, Javier can buy at maximum about 3.7 gallons of oil.

And we're done!

Wolfyy Wolfyy · Answer 2 · 2020-10-01T19:41:40+02:00

Wolfyy Wolfyy

01-10-2020

Answer:

3.7 gallons

Step-by-step explanation:

15 - 2.59 = 12.41 (money left)

12.41 / 3.39 = 3.6607669...

3.6607669... → 3.7

Best of Luck!

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1 Javier has at most $15.00 to spend today. He buys a bag of pretzels and a bottle of juice for $2.59. If gasoline at this store costs $3.39 per gallon, how many gallons of gasoline, to the nearest tenth of gallon, can Javier buy for his car?​

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1 Javier has at most $15.00 to spend today. He buys a bag of pretzels and a bottle of juice for $2.59. If gasoline at this store costs $3.39 per gallon, how many gallons of gasoline, to the nearest tenth of gallon, can Javier buy for his car?