contestada

A rectangle measures 6 3/4 cm by square root of 121 cm. What is the perimeter of the rectangle to the nearest tenth?​

Respuesta :

Answer:

35.5 cm

Step-by-step explanation:

The perimeter (P) is calculated as

P = (2 × 6.75 ) + (2 × [tex]\sqrt{121}[/tex] )

  = 13.5 + (2 × 11) = 13.5 + 22 = 35.5 cm

Answer:

35.5cm

Step-by-step explanation:

The perimeter (P) is calculated as

P = (2 × 6.75 ) + (2 × \sqrt{121}121 )

  = 13.5 + (2 × 11) = 13.5 + 22 = 35.5 cm

Otras preguntas