Answer:
Cos A = 40/41
Tan A = 9/40
Step-by-step explanation:
Sin A = [tex]\frac{perpendicular}{hypotenuse}[/tex] = [tex]\frac{9}{41}[/tex]
So,
Perpendicular = 9 , Hypotenuse = 41
So, Finding base by Pythagorean Theorem
=> [tex]c^2=a^2+b^2[/tex]
=> [tex]a^2 = c^2-b^2\\[/tex]
=> [tex]a^2 = 41^2-9^2[/tex]
=> [tex]a^2 = 1681 - 81\\a^2 = 1600[/tex]
Taking sqrt
=> base = 40
Now,
Cos A = [tex]\frac{base}{hypotenuse} = \frac{40}{41}[/tex]
Tan A = [tex]\frac{perpendicular}{base} = \frac{9}{40}[/tex]
