What is the point-slope form of a line that has a slope of -4 and passes through point (-3, 1)?
Oy-(-3) --4(x-1)
O y-1--4[*-(-3)]
0 -1-y,--4-3-x;)
O 3-y,--4(1-x)

Respuesta :

Answer:

Option B) [tex]y - 1= -4 [x-(-3)][/tex]

Step-by-step explanation:

Slope = m = -4

Point = (x1,y1) = (-3,1)

So, x1 = -3, y1 = 1

Putting it in the point slope equation:

=> [tex]y-y1 = m(x-x1)[/tex]

=> [tex]y - 1= -4 [x-(-3)][/tex]