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When the shuttle bus comes to a sudden stop
to avoid hitting a dog, it decelerates uniformly
at 3.8 m/s2 as it slows from 9.8 m/s to 0 m/s.
Find the time interval of acceleration for
the bus.
Answer in units of s

Respuesta :

meerkat18
The question is asking to calculate the time interval of acceleration for the bus and base on my own calculation, I would say that the answer would be 2.58 seconds. I hope you are satisfied with my answer and feel free to ask for more. I hope you are satisfied with my answer and feel free to ask for more 
aachen

Answer:

2.58 seconds

Step-by-step explanation:

Given: the shuttle bus comes to a sudden stop  to avoid hitting a dog, it decelerates uniformly  at [tex]3.8[/tex] [tex]\text{m}/\text{s}^2[/tex] as it slows from [tex]9.8[/tex] [tex]\text{m}/\text{s}[/tex] to [tex]0[/tex] [tex]\text{m}/\text{s}[/tex].

To Find: the time interval of acceleration for  the bus.

Solution:

Initial speed of shuttle bus [tex]\text{u}=9.8[/tex] [tex]\text{m}/\text{s}[/tex]

Final speed of shuttle bus [tex]\text{v}=0[/tex] [tex]\text{m}/\text{s}[/tex]

acceleration [tex]=3.8[/tex] [tex]\text{m}/\text{s}^2[/tex]

using first equation of motion

[tex]\text{v}=\text{u}+\text{a}\text{t}[/tex]

as speed decreases acceleration will be negative

[tex]\text{v}=\text{u}-\text{a}\text{t}[/tex]

putting value in equation

[tex]0=9.8-3.8\text{t}[/tex]

[tex]3.8\text{t}=9.8[/tex]

[tex]\text{t}=\frac{9.8}{3.8}[/tex]

[tex]\text{t}=2.58[/tex] [tex]\text{seconds}[/tex]

It takes [tex]2.58\text{s}[/tex] to decelerate to  [tex]0[/tex] [tex]\text{m}/\text{s}[/tex]

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