Respuesta :
length of a line segment = √((x₂ - x₁)² + (y₂ - y₁)²) where W contain x₁ and y₁ and X contain x₂ and y₂
= √((6 - (-6))² + (8 - (-8))²)
= √((6+6)² + (8 + 8)²)
= √((12)² + (16)²)
= √(144 + 256)
= √400
= 20 units
= √((6 - (-6))² + (8 - (-8))²)
= √((6+6)² + (8 + 8)²)
= √((12)² + (16)²)
= √(144 + 256)
= √400
= 20 units
The distance between these points W(-6, -8) and X(6, 8) will be 20 units.
What is the distance between two points?
Let one point be (x, y) and another point be (h, k).
Then the distance between the points will be
D² = (x – h)² + (y – k)²
The distance between these points W(-6, -8) and X(6, 8) will be
D² = (6 + 6)² + (8 + 8)²
D² = 12² + 16²
D² = 144 + 256
D² = 400
D = 20 units
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