Answer:
[tex](C)\dfrac{1}{4}[/tex]
Step-by-step explanation:
In a standard deck,
The table below gives the distribution of the cards.
[tex]\left|\begin{array}{c|c|c|c}&$Club&$Not a club\\----&----&---&----\\$Face card&3&9&12\\$Not a face card&10&30&40\\----&----&---&----\\$Total&13&39&52\end{array}\right|[/tex]
[tex]P($Club$ | $Not a Face Card)$=\dfrac{10}{40}\\ =\dfrac{1}{4}[/tex]
The correct option is C.