contestada

On a coordinate plane, 2 exponential functions are shown. Function f (x) approaches y = 0 in quadrant 2 and increases into quadrant 1. Function g (x) approaches y = 0 in quadrant 1 and increases into quadrant 2.

Which function represents a reflection of f(x) = Three-eighths(4)x across the y-axis?


g(x) = NegativeThree-eighths (one-fourth) Superscript x

g(x) = Negative three-eighths(4)x

g(x) = Eight-thirds(4)-x

g(x) = Three-eighths(4)–x

Respuesta :

Answer:

[tex]g(x)=f(-x)=\frac{3}{8}(4)^{-x}[/tex]

Step-by-step explanation:

The pre-image is

[tex]f(x)=\frac{3}{8}(4)^{x}[/tex]

To make a reflection across the y-axis, we need to apply the transformation

[tex](x,y) \implies (-x,y)[/tex]

Which give the function

[tex]g(x)=f(-x)=\frac{3}{8}(4)^{-x}[/tex]

Therefore, the right answer is the last choice.

Answer:

D

Step-by-step explanation:

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