Answer: 2 moles of [tex]H_2O[/tex] will be formed.
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} NaOH=\frac{80g}{40g/mol}=2moles[/tex]
The balanced chemical equation is:
[tex]H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O[/tex]
According to stoichiometry :
2 moles of [tex]NaOH[/tex] give = 2 moles of [tex]H_2O[/tex]
Thus 2 moles of [tex]NaOH[/tex] give =[tex]\frac{2}{2}\times 2=2moles[/tex] of [tex]H_2O[/tex]
Thus 2 moles of [tex]H_2O[/tex] will be formed.
