We have been given 4 points [tex](3,2), (-3,2), (-3,-3), (3,-3)[/tex]. We are asked yo plot these points on coordinate plane and find the area of the figure.
Upon plotting our given points, we will get a rectangle as shown in the attached file.
We can see that the width is 5 units that is difference between y-coordinates of point [tex](3,2)\text{ and }(3,-3)[/tex].
[tex]\text{Width}=2-(-3)=2+3=5[/tex]
We can see that the length of rectangle is 6 units that is difference between x-coordinates of point [tex](-3,2)\text{ and }(3,2)[/tex].
[tex]\text{Length}=3-(-3)=3+3=6[/tex]
We know that area of rectangle is length times width.
[tex]A=\text{Length}\times \text{Width}[/tex]
[tex]A=6\times 5[/tex]
[tex]A=30[/tex]
Therefore, the area of the figure would be 30 square units.
