Respuesta :
Answer:
Check the explanation
Step-by-step explanation:
Step-1 The smallest time is located in Job E (1 hour). Since the time is in First Work Center (Body), schedule this job first. And eliminate Job E from further consideration.
The sequence is E - ? - ? - ? - ?
Step-2 Then, the smallest time is located in Job A (2 hour). Since the time is in Second Work Center (Paint), schedule this job last. And eliminate Job A from further consideration.
The sequence is E - ? - ? - ? - A
Step -3 Then, the smallest time is located in Job D (3 hour). Since the time is in First Work Center (Body), schedule this job after E. And eliminate Job D from further consideration.
The sequence is E - D - ? - ? - A
Step-4 Then, the smallest time is located in Job B (4 hour). Since the time is in Second Work Center (Paint), schedule this job second last. And eliminate Job B from further consideration.
The sequence is E - D - ? - B - A
Step-5 The only job left to consider is Job C.
The sequence is E - D - C - B - A
a) Where in the optimum sequence will the car A be scheduled?
Answer: Option E – Fifth Position. Refer the sequence for the same based on the Johnson’s rule of sequence.
b). What is the optimum sequence (first car to last)?
Answer : Option B : The sequence is E; D; C; B; A
c) What is the idle time at the paint work center for the optimal schedule?
Answer : C. 4 hours