Answer:
C is the answer, based on coordinates T = -2,0 they both distribute better as QPT = RA triangle base 10cm and point of origin is central to the base at point O. Length PO = Length TO
Therefore, Coordinates Q (2,2) can prove T = (-2.0) as xy is 2 units from point of origin for both sides, each.
Step-by-step explanation:
Proof same length/area.
Lets just say area is 25 and all lengths of 5 each 5x5 -25
Then for triangle QPT to have same area it would need to have one side 5 and then we work a second right angle at OQ = diagonal = √ 25+ √ 25 = √ 50 = √ QP + √ PO = √ OQ Diagonal = √ 50 = 7.07106781187
OQ = 7.07
Cos (45)degree x 7.07106781187 = 5
We just need to redo as a long rectangle to find the longer diagonal using cos also.
We make a new letter above the T called S
SRQ = 15 sq +5sq = √225 + √25
= SRQsq √250 = 15.81cm
We can check area OPQR = 5x5 = 25
We can now check area QPT 7.5 x 5= 37.5
We can see its not to scale so length PT must be 10 to 1/2 and be 10 value to share same area. Area QPT = 1/2 10 x 5 = 25 and now match QPT.
coordinates 2, 2 = Q
coordinates -8, -3 = T = as we found -10 in run and -5 in rise
But as Q = 2,2 meaning 2 in run from origin zero this means equal side from origin would be found at T.
Therefore T = -2, 0
We do not need to count the length we only need to match Q and recognize Q's value to the origin =x= 2
T therefore = x=-2
All options show y value 0, which means the scale of the square = 2cm
Answer:
C (-2,0)
Step-by-step explanation:
because O is the origin, it = (0,0)
you subtract the x coordinates to find the width which will be 2 because the x value of Q is 2
because OPQR is a square, RQ=RO=OP=QP=2 and the area of the square is 4
triangle PQT would be 4
the height of the triangle is TP and the width is QP and the area is 4
we know QP=2
the formula for the area of the triangle is length x width ÷2
TP•QP÷2=4
TP•QP=8
2TP=8
TP=4
the x value of Q coordinate - TP= 2-4=-2
so T would be (0,-2)
