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If the frequency of an allele ("A") for an STR locus is 0.02 and the frequency of another allele ("B") for the same locus is 0.03, what is the probability that a member of that population is heterozygous ("AB") for the above alleles?

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luisvaschetto

Answer:

Heterozygous (AB) for the STR locus = Allele (A) x allele (B) = 0.02 x 0.03 = 0.0006

Explanation:

The probability of the heterozygous genotype AB is equal to the product of the probabilities of these two independent events (i.e., independent events represented by allele segregation)= 0.02 x 0.03 = 0.0006

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