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A balloon contains 2500. mL of Helium at 75.00°C. When the temperature is lowered to
-25.00 °C and the pressure remains unchanged, what is the new volume?

Respuesta :

917006450984help

Answer:

+75°C = 273+75 = 348 K

-25 °C = 273 - 25=248 K

now as at constant pressure, V/T = constant

so

2500/348 = V/248

Explanation:

V = 2500/348 × 248 = 1781.6 mL

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