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The period is found by dividing [tex] \pi [/tex] by whatever is being multiplied by x. In this case, x is being multiplied by the fraction 3/5. You have to divide [tex] \pi [/tex] by 3/5. In the world of fractions this means you can multiply [tex] \pi [/tex] by 5/3. This give you 5/3[tex] \pi [/tex] as your period. See attached picture for example and let me know if this confuses you.
Ver imagen kaylenecuthberson

The period of the function y=3/2cot(3/5x)+5 will be [tex]5\pi[/tex]/3.

what is period?

In algebraic geometry, a period is a number that can be expressed as an integral of an algebraic function over an algebraic domain.

The period is found by dividing  by whatever is being multiplied by x. In this case, x is being multiplied by the fraction 3/5.

You have to divide  by 3/5. In the world of fractions this means you can multiply  by 5/3. This give you 5/3 as your period.

[tex]y=\dfrac{3}{2}Cot(\dfrac{3x}{5})+5[/tex]

[tex]\dfrac{\pi}{\dfrac{3}{5}}\ \ \ \ or \ \ \ \ \dfrac{5\pi}{3}[/tex]

So the period will be [tex]\dfrac{5\pi}{3}[/tex]

To know more about period follow

https://brainly.com/question/558692

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