Answer:
0.0833 moles of O₂
Explanation:
Most usual Law to solve this sort of problem, is the Ideal Gases Law
Pressure . Volume = number of moles . R . Temperature
where R is the Ideal Gases Constant → 0.082 L.atm/mol.K
First of all we need to convert the pressure from kPa to atm, because the Units of R
320 kPa . 1 atm / 101.3 kPa = 3.16 atm
Now, you replace data:
3.16 atm . 0.45L = mol . 0.082 L.atm/mol.K . 280K
(3.16 atm . 0.45L) / (0.082 L.atm/mol.K . 280K) = mol
0.0833 moles of O₂
