Answer:
26.33mL
Explanation:
In solving this question, we apply the general gas equation
(P1×V1)/T1 = (P2×V2)/T2
P1= initial pressure of the gas=0.974atm
V1= intial volume the gas occupies =27.5mL
T1=initial temperature of the gas =22°C =22+273K=295K
P2 = Final pressure of the gas = 0.993atm
V2= final volume of the gas = ?
T2 = final temperature of the gas = 15°C = 15+273=288K
From (P1×V1)/T1 = (P2×V2)/T2, we make V2 subject of formula
V2=(P1×V1×T2)/(P2×T2)
We substitute the given values
V2=(0.974×27.5×288)/(0.993×295)
V2=7714.08/292.935
V2=26.33mL
