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Predict the precipitate produced by mixing a(n) Al(NO3)3 solution with a(n) NaOH solution. Write the molecular equation for the reaction. (Use the lowest possible coefficients. Include states-of-matter under SATP conditions in your answer.)

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Answer:

Al(NO₃)₃ (aq) + NaOH(aq) → Al(OH)₃ (s)↓ + 3NaNO₃ (aq)

Explanation:

Al³⁺ cation can generate a precipitate when it bonds to OH⁻ from a strong base but it is important to the base, not to be in excess.

When the OH⁻is in excess, the produced aluminium hydroxide will be soluble.

Al³⁺(aq) + 3OH⁻(aq) ⇄ Al(OH)₃(s) ↓    Kps