Explanation:
When coil is placed in the magnetic field , the flux attached with it can be found by the relation . Flux Ф = the dot product of magnetic field and area of coil .
Thus Ф = B A cosθ
here B is magnetic field strength and A is the area of coil .
The angle θ is the angle between coil and field direction .
When coil rotates , the angle varies . By which the flux varies . The emf is produced in coil due to variation of flux . The relation for this is
The emf produced ξ = - [tex]\frac{d\phi}{dt}[/tex] = B A sinθ [tex]\frac{d\theta}{dt}[/tex]
Now in the given problem
5 = 0.38 x A x [tex]\frac{d\theta}{dt}[/tex] I
Now if the magnetic field is 0.55 T and all the other terms are same , the emf produced
ξ = 0.55 x A x [tex]\frac{d\theta}{dt}[/tex] Ii
dividing II by I , we have
[tex]\frac{\xi}{5}[/tex] = [tex]\frac{0.55}{0.38}[/tex] = 1.45
or ξ = 7.2 V