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A wire with current I = 15 A flows at an angle of 30 degrees to the direction of a uniform magnetic field of 0.9 T. What is the magnitude of the force exerted on a 10 m length of wire? (in units of N)

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opudodennis

Answer:

67.5

Explanation:

[tex]F= BILsin\theta[/tex] where F is the magnitude of the force, B is the magnetic field, I is current, [tex]\theta[/tex] is the angle of inclination, L is the length of the wire.

Substituting 0.9 T for magnetic field B, 10 m for length, 15 A for current I and 30 degrees for [tex]\theta[/tex] then

[tex]F=0.9\times 15\times 10\times sin 30^{\circ}=67.5[/tex]

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