Respuesta :
The question is incomplete, here is the complete question:
A(aq) + B(aq) → 2C(aq)
If the value of Kc for the reaction is 434, what is the concentration of C at equilibrium if initial concentrations of A and B are both 0.500 M. (Hint: Everything is squared after you set-up the equilibrium expression with the values given.
Answer: The concentration of C at equilibrium is 0.912 M
Explanation:
We are given:
Initial concentration of A = 0.500 M
Initial concentration of B = 0.500 M
The given equation follows:
[tex]A(aq.)+B(aq.)\rightarrow 2C(aq.)[/tex]
Initial: 0.5 0.5
At eqllm: 0.5-x 0.5-x 2x
The expression of [tex]K_c[/tex] for above equation follows:
[tex]K_c=\frac{[C]^2}{[A][B]}[/tex]
We are given:
[tex]K_c=434[/tex]
Putting values in above equation, we get:
[tex]434=\frac{(2x)^2}{(0.5-x)\times (0.5-x)}\\\\x=0.456,0.553[/tex]
Neglecting the value of x = 0.553 M because the equilibrium concentration of A and B will become negative, which is not possible
So, equilibrium concentration of C = 2x = 2(0.456) = 0.912 M
Hence, the concentration of C at equilibrium is 0.912 M
