Answer:
So three lowest possible values of d ar 0.85m, 2.55m and 4.25m
Explanation:
The wavelength of wave:
λ=v/f
λ=340/200=1.7m
The destructive interference condition is:
Δd=(m+1/2)λ where m=0,1,2,3........
For minimum destructive interference ,the value of m is equal to zero
Δd=(0+1/2)×1.7
Δd=0.85m
For m=1
Δd=(1+1/2)×1.7
Δd=2.55m
For m=2
Δd=(2+1/2)×1.7
Δd=4.25m
So three lowest possible values of d ar 0.85m, 2.55m and 4.25m