The probability that a person in the United States has type B​+ blood is 13​%.
Four unrelated people in the United States are selected at random.
Complete parts​ (a) through​(d).

(a) Find the probability that all four have type B​+ blood.The probability that all four have type B​+ blood is?
​(Round to six decimal places as​ needed.)
​(b) Find the probability that none of the four have type B​+ blood.The probability that none of the four have type B​+ blood is?
​(Round to three decimal places as​ needed.)
​(c) Find the probability that at least one of the four has type B​+ blood.The probability that at least one of the four has type B​+ blood is?
​(Round to three decimal places as​ needed.)
​(d) Which of the events can be considered​ unusual? Explain. Select all that apply.
A.None of these events are unusualNone of these events are unusual.
B.The event in part​ (a) is unusual because its probability is less than or equal to 0.05.
C.The event in part​ (b) is unusual because its probability is less than or equal to 0.05.
D.The event in part​ (c) is unusual because its probability is less than or equal to 0.05.

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Answer:

Step-by-step explanation:

Given that the probability that a person in the United States has type B​+ blood is 13​%.

Since four unrelated people in the United States are selected at random, we can say that each person is independent of the other to have B+ blood group.

Let X be the number of persons who have blood group B+ in the group of 4 persons.

X is Binomial with p = 0.13

a) P(X = 4) = [tex](0.13)^4 = 0.000286[/tex]

b) P(x =0) = [tex](1-0.13)^4 = 0.572898[/tex]

c) [tex]P(X\geq 10 = 1-P(0) = 0.427102[/tex]

d) All having B+ is unusual since probability is very negligible