Answer:
[tex]N_A=21.68N[/tex]
Explanation:
We already know that the wight in reference is gravitational force on an object:[tex]F_G=mg[/tex].
Gravity=[tex]9.8m/s^2[/tex]
Weight of car=0.800kg
To solve for A, we apply Newton's second law of radial direction:
[tex]\sum F_r_a_d=ma_R\\=mg+N_B\\[/tex]
Rewrite to calculate acceleration,[tex]a[/tex]:
[tex]a_R=\frac {mg+N_B}{m}\\=\frac{0.8kg+9.8m/s^2+6N}{0.8kg}=17.3m/s^2[/tex]
Solving for Position A:
[tex]\sum F_r_a_d=ma_R\\=N_A-mg\\N_A=ma_R+mg=0.8kg(17.3m/s^2+9.8m/s^2)\\=21.62N[/tex]
