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At Central Online High School, 45100 of the students have a dog, 30100 of the students have a cat, and 18100 of the students have both a dog and a cat.

What is the probability that students who have a cat also have a dog?

Enter your answer as a fraction in simplest form, formatted like this: 3/14

Respuesta :

Answer:

p=[tex]\frac{181}{301}[/tex]

Step-by-step explanation:

30100 have dogs, 18100 have cats.

The question simply asks for a union scenario thus the law of AND & OR is applicable.

Therefore:-Those who have both cats and dogs partially have cats.

[tex]P(X=both \ cat \ and \ dog)=\frac{18100}{30100}\\p=\frac{181}{301}[/tex]

Answer:

3/5

Step-by-step explanation:

The correct answer is 3/5 i just did the workbook