Answer:
[tex]1.06\times 10^6 J[/tex]
Explanation:
We are given that
[tex]V_1=6 V[/tex]
[tex]V_2=-5 V[/tex]
Charge on 1 electron, 1 e=[tex]-1.6\times 10^{-19} C[/tex]
Avogadro's number, [tex]N_A=6.02\times 10^{23}[/tex]
[tex]q=ne[/tex]
[tex]q=6.02\times 10^{23}\times 1.6\times 10^{-19}=-9.632\times 10^4 C[/tex]
[tex]W=q\Delta V[/tex]
[tex]W=q(V_2-V_1)[/tex]
[tex]W=-9.632\times 10^4\times (-5-6)=1.06\times 10^6 J[/tex]
Hence, the work done=[tex]1.06\times 10^6 J[/tex]
