Respuesta :
7x - 2y = -6 . . . . . . . (1)
8x + y = 3 . . . . . . . . .(2)
From (2): y = 3 - 8x
substituting for y in (1), we have,
7x - 2(3 - 8x) = -6
7x - 6 + 16x = -6
23x = 0
x = 0
y = 3 - 8(0)
y = 3
Therefore, solution = (0, 3)
8x + y = 3 . . . . . . . . .(2)
From (2): y = 3 - 8x
substituting for y in (1), we have,
7x - 2(3 - 8x) = -6
7x - 6 + 16x = -6
23x = 0
x = 0
y = 3 - 8(0)
y = 3
Therefore, solution = (0, 3)
The solution to the system of linear equations 7x – 2y = –6 and 8x + y = 3 is (0,3)
How to determine the solution?
The equations are given as:
7x – 2y = –6
8x + y = 3
Multiply the second equation by 2
16x + 2y = 6
Add this equation and the first equation
16x + 7x + 2y - 2y = 6 - 6
Evaluate
23x = 0
Divide by 23
x = 0
Substitute x = 0 in 7x – 2y = –6
7(0) – 2y = –6
This gives
-2y = -6
Divide by -2
y = 3
Hence, the solution to the equations is (0,3)
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