A student performs an experiment that produces 5.78 grams of silver chloride. He calculated that 7.25 grams of silver chloride should have precipitated if all of the limiting reactant reacted. What is his percent yield?

Respuesta :

Answer:

79.7%

Explanation:

Given:

Actual yield obtained by the student on performing the experiment is 5.78 g.

Theoretical yield calculated by the student is 7.25 g.

Now, the percent yield of silver chloride is given as the ratio of actual yield to theoretical yield expressed a percentage.

So, the percent yield is given as:

[tex]\%\ yield=\frac{Actual\ yield}{Theoretical\ yield}\times 100[/tex]

Plug in the given values and solve for the percent yield. This gives,

[tex]\%\ yield=\frac{5.78}{7.25}\times 100\\\\\%\ yield=\frac{578}{7.25}\\\\\%\ yield=79.7\%[/tex]

Therefore, the percent yield is 79.7%.