at 25.0c helium molecules have an average velocity of 1.26x10^5 cm/s and methane molecukes have an average velocity of 6.30x10^4 cm/s calculate the kinetic energy of each type of molecule at 25.0c and determine which is greater

Respuesta :

Answer:

  • Both average kinetic energies are equal to 3.18 × 10³ J/mol

Explanation:

The average  kinetic energy of gas particles depends only on the temperature. Thus you must expect that the average kinetic energies of both helium gas and methane gas at 25ºC are equal.

1. Kinetic energy of helium molecules

    The mass of 1 mole of molecules of helium is 4 grams. Convert to kg, to use SI units: 0.004 kg

   Convert the velocity to m/s: 1.26×10⁵ cm/s = 1.26 × 10³ m/s

        [tex]KE=\dfrac{1}{2}mv^2=\dfrac{1}{2}(0.004kg/mol)(1.26\times 10^3m/s)=3.18\times 10^3J/mol[/tex]

2.  Kinetic energy of methane molecules

    The mass of 1 mole of molecules of methade is 416 grams. Convert to kg, to use SI units: 0.016 kg

   Convert the velocity to m/s: 6.30×10⁴ cm/s = 6.30 × 10⁴ m/s

        [tex]KE=\dfrac{1}{2}mv^2=\dfrac{1}{2}(0.016kg/mol)(6.30\times 10^2m/s)=3.18\times 10^3J/mol[/tex]

As expected both average kinetic energies are the same.