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A person wishes to mix coffee worth ​$9 per lb with coffee worth ​$3 per lb
to get 120 lb
of a mixture worth $5 per lb
How many pounds of the $9 and the ​$3 coffees will be​ needed?

Respuesta :

meerkat18
To answer the question, let x be the number of pounds of coffee worth $9. Having said that, the number of pounds of coffee worth $3 is 120 - x. The equation relating the items before and after mixing is,
                      (x)($9) + (120 - x)($3) = (120)($5)
The value of x is 40. Therefore, the amount of coffee worth $9 and $3 to be used are 40 and 80 pounds, respectively.

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