See the graph below
Explanation:
First of all, let's rename those expressions as follows:
[tex]\left\{ \begin{array}{c}y=10+3x\\y=4x\end{array}\right[/tex]
So we we have two lines written in slope-intercept form. In order to graph those lines, let's find two points for each:
First line:
[tex]For \ x=0: \\ \\ y=10+3(0) \\ \\ y=10 \\ \\ \\ For \ x=-10/3: \\ \\ y=10+3(-10/3) \\ \\ y=10-10 \\ \\ y=0 \\ \\ \\ So \ the \ line \ passes \ through \ (0,10) \ and \ (-10/3,0)[/tex]
This line is the green one shown below.
Second line:
[tex]For \ x=0: \\ \\ y=4(0) \\ \\ y=0 \\ \\ \\ For \ x=1: \\ \\ y=4(1) \\ \\ y=4 \\ \\ \\ So \ the \ line \ passes \ through \ (0,0) \ and \ (1,4)[/tex]
This line is the red one shown below.
Learn more:
Shifting graphs: https://brainly.com/question/10010217
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