Respuesta :
Answer:
Explanation:
Given
initial Pressure [tex]P_1=90\ psia[/tex]
elevation [tex]z_1=16\ ft[/tex]
Final Pressure [tex]P_2=30\ psia[/tex]
elevation [tex]z_2=450\ ft[/tex]
Pressure after Pumping(pump inlet pressure ) is given by
[tex]P_{after\ pump}=P_{top}+\Delta P[/tex]
[tex]\Delta P=\rho gh[/tex]
where [tex]\rho [/tex]=density of water[tex](62.2\ lbm\ft^3)[/tex]
g=acceleration due to gravity[tex](32.2\ ft/s^2)[/tex]
h=elevation
[tex]\Delta P=62.2\times 32.2\times (16+450)\times \frac{1\ lbf}{32.174\ lbm\ ft}[/tex]
[tex]\Delta P=28,985\ lbf/ft^2[/tex]
[tex]\Delta P=201.3\ lbf/in.^2[/tex]
[tex]P_{after\ pump}=30+201.3=231.3\ lbf/in.^2[/tex]
Pressure required to be applied
[tex]\Delta P_{pump}=P_{after\ pump}-P_{bottom}[/tex]
[tex]\Delta P_{pump}=231.3-90=141.3\ psi[/tex]
