Answer:
Explanation:
Given
Altitude from which Diver steps out [tex]H=4000\ m[/tex]
altitude at which diver opens the Parachutes [tex]h=760\ m[/tex]
total height covered by diver[tex]=H-h=4000-760=3240\ m[/tex]
Initial velocity of diver is zero
using equation of motion
[tex]s=ut+\frac{1}{2}at^2[/tex]
where s=displacement
u=initial velocity
a=acceleration
t=time
[tex]3240=0+\frac{1}{2}\times 9.8\times t^2[/tex]
[tex]t^2=661.224[/tex]
[tex]t=25.71\ s[/tex]
