An anhydrous (water removed) salt has a formula mass of 160.167 g/mol. If the hydrated version of the salt has 8 mol of water associated with it, what is the mass % of water in the hydrated salt? Report your answer to three digits after the decimal.

Respuesta :

Answer: 47.34%

Explanation:

Mass of anhydrous salt = 160.167g/mol

Mass of the hydrate salt = 160.167 + 8(18)

160.167 + 144 = 304.167g

% Mass of water in the hydrate salt =

(144/304.167) x 100 = 47.34%