Answer:
30 N
Explanation:
We are given that
Force,F =9 N
Charge,q=3 C
We have to find the exact magnitude of the force(in N) exerted by the system of charges on the 10.0 C.
We know that
[tex]E=\frac{F}{q}[/tex]
Using the formula
[tex]E=\frac{9}{3}=3 N/C[/tex]
Now, charge=10 C
The electric field remains same then
[tex]F=3\times 10=30 N[/tex]
Hence, the exact magnitude of the force exerted by the system of charges on the 10 C=30 N