Answer:
297.8 m
Explanation:
We are given that
Acceleration=[tex]a=1.65m/s^2[/tex]
Time,t=19 s
We have to find the distance covered by the train when it reach its top speed if starting from rest.
Initial speed=u=0
[tex]s=ut+\frac{1}{2}at^2[/tex]
Using the formula
[tex]s=0(19)+\frac{1}{2}\times 1.65(19)^2[/tex]
[tex]s=297.8 m[/tex]
Hence, the train covered 297.8 m when the train go to reach its top speed if starting from rest.
