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A 20.5 kg box initially at rest is pushed 5.93 m along a rough, horizontal floor with a constant applied horizontal force of 95.3501 N. If the coefficient of friction between box and floor is 0.389, find the work done by the applied force.

Respuesta :

Answer:

 W= 565.42 J

Explanation:

Given that

mass , m =20.5 kg

displacement = 5.93 m

Applied force ,F= 95.3501 N

Coefficient of friction ,μ = 0.389

We know that work done by force F is given as

W= F .d

d=Displacement

F=Force

W=Work

W= 95.3501 x 5.93 J

W= 565.42 J

Therefore the work done by applied force will be  565.42 J.