Answer:
The correct option is D. 2/7
Step-by-step explanation:
Consider the provided information.
There are 8 volunteers including Andrew and Karen, 4 people are to be selected at random to organize a charity event.
We need to determine the probability Andrew will be among the 4 volunteers selected and Karen will not.
We want to select Andrew and 3 others but not Karen in the group.
Thus, the number of ways to select 3 member out of 8-2=6
(We subtract 2 from 8 because Andrew is already selected and we don't want Karen to be selected, so subtract 2 from 8.)
The required probability is:
[tex]\dfrac{^6C_3}{^8C_4}=\dfrac{\frac{6!}{3!3!}}{\frac{8!}{4!4!}}\\\\\\\dfrac{^6C_3}{^8C_4}=\frac{20}{70}\\\\\\\dfrac{^6C_3}{^8C_4}=\dfrac{2}{7}[/tex]
Hence, the correct option is D. 2/7
