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Jennifer got a box of chocolates. The box is a right triangular prism shaped box. It is 7 inches long, and the triangular base measures 2 in x 3in x 4in. What is the surface area of the box of chocolates?

Respuesta :

Answer:

68.8 sq. inches.

Step-by-step explanation:

The triangular surfaces have sides 2 in by 3 in by 4 in.

So, half perimeter, s = [tex]\frac{2 + 3 + 4}{2} = 4.5[/tex]

So, the area of the triangular face is [tex]\sqrt{s(s - 4)(s - 2)(s - 3)} = \sqrt{4.5 \times 0.5 \times 2.5 \times 1.5} = 2.9[/tex] sq. inches.

Now, the total surface area of the right triangular prism will be (2.9 × 2) + 7(2 + 3 + 4) = 68.8 sq. inches. (Answer)