Answer:
a = 16.4 m/s²
Explanation:
given,
initial speed of the aircraft, u = 295 Km/h
1 km/h = 0.278 m/s
u = 295 x 0.278 = 82.01 m/s
final speed, v =0 m/s
distance, d = 205 m
using equation of motion
v² = u² + 2 a s
0² = 82.01² - 2 x a x 205
410 a = 82.01²
a = 16.4 m/s²
the deceleration of the aircraft is equal to 16.4 m/s²
