Answer:
x = 600 Km
Explanation:
given,
speed of transverse wave = 4.05 Km/s
speed of longitudinal wave = 7.695 Km/s
difference of the time of arrival of wave = 69.9 s
now,
t₂ - t₁ = 69.9 s
let x be the distance
[tex]\dfrac{x}{4.05} - \dfrac{x}{7.695} = 69.9[/tex]
[tex]x = \dfrac{69.9\times 4.05 \times 7.695}{7.695-4.05}[/tex]
x = 597.645 Km
x = 600 Km
distance of recorder from the site is 600 Km approximately.